4k+8, (2k^2+3k+6) ,3k^2+4k+4 are in arithmetic progression find the value of k .
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Solution: An arithmetic progression (AP) is a sequence where the differences between every two consecutive terms are the same. k² + 4k + 8, 2k² + 3k + 6 and 3k² + 4k+ 4 are consecutive terms of an AP. Therefore, k is 0.
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