Question

4k bytes words
32 bits each
What is the total number of bits in memory

Answer 1

Answer:

Explanation:

1

A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory size that is cacheable is 1024 Mbits. Assuming that the addressing is done at the byte level, show the format of main memory addresses using 8-way set-associative mapping.

So here's what I have understood from this question so far: Line size = 8 words = 2^3, which means that w = 3; Cache size = 4K = (2^3 + 2^6)/(2^3) = 2^6 lines; 8-way set associative means that each cache contains (2^6)/(2^3) = 2^3 Main memory size = 1024 Mbits = 128 M

I am stuck as to how to proceed next. Any help would be greatly appreciated.