Question

4ka power 7*4ka power 8*1 upon 4aur 4ka power 9​

Answer 1

its difficult to understand what you are talking of yet i framed a question but I am not sure its exactly what u ment

Question

(4⁷×4⁸*¹)

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(4*4⁹)

we know that a^m×a^n=a^m+n using it in question

Solution

4^7+8

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4^1+9

4^15

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4^10 after solving

1024 ans

Hope it helps

pls mark me brainliest

Answer 2

$\huge \star \; \bf \underbrace {ANSWER} \: \star$

‣ Given :

$4^{7} × 4^{8} × \frac{1}{4} × 4^{9}$

‣ To Find :

The resultant value

‣ Solution :

$\rightarrow 4^{7} × 4^{8} × \frac{1}{4} × 4^{9}$

$= 4^{7} × 4^{8} × 4^{-1} × 4^{9}$

$= 4^{7 + 8 - 1 + 9}$

$= 4^{23}$

$\implies \sf {\underline{Hence, \: the \: answer \: is \: 4^{23}.}}$