4L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is ________ .
(a) 0.004
(b) 0.008
(c) 0.012
(d) 0.016
Plsss reply Nilesh!
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☆ ANSWER ☆
Option D is the correct answer.
Given:- V1 = 4L
V2 = 5L
M1 = 0.02 M
To find:- M2
Formula to be used:- M1V1 = M2V2
Solution:-
M2 = M1V1/V2
M2 = 0.02×4/5
M2 = 0.016.
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