Question

(4lpower 5 - 6lpower4+8lcube)/2lsquare​

Answer 1

Answer:

$\red {\frac{\left( 4l^{5} - 6l^{4} + 8l^{3}\right)}{2l}}$

$\green { = l^{2} ( 2l^{2} - 3l + 4) }$

Step-by-step explanation:

$\frac{\left( 4l^{5} - 6l^{4} + 8l^{3}\right)}{2l}$

$= \frac{ 2l\left( 2l^{4} - 3l^{3} + 4l^{2} \right)}{2l}$

$= 2l^{4} -3l^{3} + 4l^{2}$

$= l^{2} ( 2l^{2} - 3l + 4)$

Therefore.,

$\red {\frac{\left( 4l^{5} - 6l^{4} + 8l^{3}\right)}{2l}}$

$\green { = l^{2} ( 2l^{2} - 3l + 4) }$

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