Question

4m+6n=54;3m+2n=28 by substituting method

Answer 1

Solution:

4m+6n=54 (i)

3m+2n=28 (ii)

By substitution method:

From eq – (i)

4m+6n=54

or, 4m= 54-6n

or, m= 54-6n/4

substitute the value of m in eq (ii)

3m+2n=28

or, 3(54-6n/4)+2n=28

or, 162-18n/4+2n=28

Taking LCM in RHS

or, 162-18n-8n/4=28

or, 162-10n=28×4

or, 162-10n=112

or, -10n=112-162

or, -10n=-50

or, n= -50/-10

or, n=5

Putting the value of n in eq (ii)

3m+2n=28

or, 3m+2×5=28

or, 3m+10=28

or, 3m=28-10

or, 3m=18

or, m=18/3

or, m=6

So, n=5 and m=6

Answer 2

Answer:

n=5 and m=6

Step-by-step explanation:

4m+6n=54 (i)

3m+2n=28 (ii)

By substitution method:

From eq – (i)

4m+6n=54

or, 4m= 54-6n

or, m= 54-6n/4

substitute the value of m in eq (ii)

3m+2n=28

or, 3(54-6n/4)+2n=28

or, 162-18n/4+2n=28

Taking LCM 4 in LHS

or, 162-18n-8n/4=28

or, 162-10n=28×4

or, 162-10n=112

or, -10n=112-162

or, -10n=-50

or, n= -50/-10

or, n=5

Putting the value of n in eq (ii)

3m+2n=28

or, 3m+2×5=28

or, 3m+10=28

or, 3m=28-10

or, 3m=18

or, m=18/3

or, m=6

So, n=5 and m=6