Question

4m+6n=54 , 3m+2n=28 हे समीकरण क्रेमरच्या पद्धतीने सोडावा​

Answer 1

4m + 6n = 54 <-- equation 1

3m + 2n = 28 <--equation 2

From equation 1, we get :

4m + 6n = 54

6n = 54 - 4m <-- equation 3

Multiply equation 2 by 3

(3m + 2n = 28) × 3

9m + 6n = 84 <-- equation 4

Now from equation 3 we know that

6n = 54 - 4m

Therefore put the value of 6n in equation 4

• 9m + 6n = 84
• 9m + (54 - 4m) = 84
• 9m + 54 - 4m = 84
• 9m - 4m + 54 = 84
• 5m = 84 - 54
• 5m = 30
• m = 30 ÷ 5
• m = 6

Now put the value of m in equation 2

• 3m + 2n = 28
• 3(6) + 2n = 28
• 18 + 2n = 28
• 2n = 28 - 18
• 2n = 10
• n = 10 ÷ 2
• n = 5