Chemistry, asked by eldhasarijamuna, 7 months ago

4Mg + 10HNO3 + 4Mg(NO3)2 +NH4NO3+3H2O
The amount of magnesium required to
reduce 1 mole of HNO3 in the reaction
is
(A) 969
(B) 489
(C) 9.65
(D) 4.89

Answers

Answered by yellasuresh7615

4

Answer:

(C)

Explanation:

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