Math, asked by sucheta7649, 6 hours ago

(4mn-2m²n+3m)-(5mn²+9m²n)-(4mn-mn²-3m)​

Answers

Answered by BATTLEGROUNDSINDIA
1

Answer:

m^2 n(mn-n^3+4m)

Step-by-step explanation:

(2m^3 n^2-m^2 n^4) - (4m^2 n^3+2m^3 n^2) + (4m^3 n-3m^3 n^2)

so,(1m^3 n^2)-(m^2 n^4)+(4m^3n)

m^2 n(mn-n^3+4m) [by taking common]

hope it helps you...

Answered by BATTLEGROUNDSINDIA
2

Answer:

m^2 n(mn-n^3+4m)

Step-by-step explanation:

(2m^3 n^2-m^2 n^4) - (4m^2 n^3+2m^3 n^2) + (4m^3 n-3m^3 n^2)

so,(1m^3 n^2)-(m^2 n^4)+(4m^3n)

m^2 n(mn-n^3+4m) [by taking common]

hope it helps you...

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