Question

4NH3-502 → 4NO-6H20 For the reaction (g) (9) (g) when 1 mole of NH3 and 1 mole of O2 are allowed to react the mass of NO produced



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Answer 1

Answer:

24g

as O2 is the limiting agent.

1 mole of O2 will form 4/5 mole of NO

4/5 mole of NO is 24g

hope this will help you.