4ohm
4. A current of 1.6mA flows through a conductor. If charge of electron is
-1.6x10^-19 coulomb, the number of electrons that will pass each second through
the cross section of that conductor is (^ represent to the power) * IT
(1 Point)
10^14
10^15
10^16
10^17
Answers
Answered by
1
Answer:
option-c 10^16
Explanation:
we know
I=Q/t and Q=ne so, I=ne/t
putting the values
1.6*10^-3=n* 1.6*10^-19
n=(1.6*10^-3)/(1.6*10^-19)
n=10^-3+19
n=10^16. (answer).
Answered by
0
Answer:
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Explanation:
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