4p^2+9q^2=6pq than 8p^3 +27q^3
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Answered by
1
Answer:
Step-by-step explanation:
4p²+ 9q²= 6pq
( 2p + 3q)² - 2 (2p) ( 3q ) = 6pq
( 2p + 3q )² - 12pq = 6pq
( 2p + 3q )² = 6pq + 12pq
( 2p + 3q )² = 18pq
( 2p + 3q ) = √18pq
∴ 8p³ + 27q³ = ( 2p )³ + (3q)³
= ( 2p+ 3q)³ - 3 (2p)(3q) (2p +3q )
= ( √18pq )³ - 18pq ( √18pq )
= 18pq (√18pq ) - 18pq (√18pq )
= 0 is the answer.
Answered by
2
Answer:
The answer is 0
Step-by-step explanation:
Hope it helps
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