Question

4p+[3q-2r(p-q+r)],p=1,q=2,r=-1

Answer 1

$\LARGE\textsf{\underline\textcolor{aqua}{↭ GiVeN :-}}$

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• p = 1
• q = 2
• r = - 1

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ To FiNd :-}}$

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↦ The product of the given equation

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$\LARGE\textsf{\underline\textcolor{aqua}{↭ SoLuTiOn :-}}$

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$\qquad\tt{:}\longrightarrow\large\textsf{4p + [ 3q - 2r ( p - q + r )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{( 4 × 1 ) + [ ( 3 × 2 ) - ( 2 × - 1 ) [ 1 - 2 + ( - 1 )]]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - ( - 2 ) ( - 1 - 1 )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + 2 ( - 2 ) ]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 + ( - 4 )]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + [ 6 - 4 ]}$

$\qquad\tt{:}\longrightarrow\large\textsf{4 + 2}$

$\qquad\tt{:}\longrightarrow\boxed{\large\textsf\textcolor{red}{8}}$