Question

4p-5q+8r;6q-7r-3p add algebraic expression ​

Answer 1

$(4p - 5q + 8r) + (6q - 7r - 3p)$

$= 4p - 5q + 8r + 6q - 7r - 3p$

$= 1p + 1q + 1r$

Or simply,

$p + q + r$

Hope you like the answer!

Answer 2

1st Answer

$\sf \dashrightarrow 3x + 7y + (9x - 11y)$

$\sf \dashrightarrow 3x + 7y + 9x - 11y$

$\sf \dashrightarrow 3x + 9x + 7y - 11y$

$\sf \dashrightarrow 12x - 4y$

2nd Answer

$\sf \dashrightarrow 4p - 5q + 8r + (6q - 7r - 3p)$

$\sf \dashrightarrow 4p - 5q + 8r + 6q - 7r - 3p$

$\sf \dashrightarrow 4p - 3p - 5q + 6q + 8r - 7r$

$\sf \dashrightarrow 1p + 1q + 1r$

$\sf \dashrightarrow p + q + r$

3rd Answer

$\sf \dashrightarrow 10a - 9b + 3c + (10b - 7a + c)$

$\sf \dashrightarrow 10a - 9b + 3c + 10b - 7a + c$

$\sf \dashrightarrow 10a - 7a - 9b + 10b + 3c + c$

$\sf \dashrightarrow 3a + 1b + 4c$

$\sf \dashrightarrow 3a + b + 4c$

4th Answer

$\sf \dashrightarrow {4m}^{2} - 3m + 5 + ({3m}^{2} - 2)$

$\sf \dashrightarrow {4m}^{2} - 3m + 5 + {3m}^{2} - 2$

$\sf \dashrightarrow {4m}^{2} + {3m}^{2} + 5 - 2 - 3m$

$\sf \dashrightarrow {7m}^{2} + 7 - 3m$

5th Answer

$\sf \dashrightarrow {6b}^{2} - 5 + 7b + (2b - {5b}^{2})$

$\sf \dashrightarrow {6b}^{2} - 5 + 7b + 2b - {5b}^{2}$

$\sf \dashrightarrow {6b}^{2} - {5b}^{2} + 7b + 2b - 5$

$\sf \dashrightarrow {1b}^{2} + 9b - 5$

$\sf \dashrightarrow {b}^{2} + 9b - 5$

6th Answer

$\sf \dashrightarrow {3a}^{2}{b}^{2} - 2ab + (10 - {2a}^{2}{b}^{2} + 2ab)$

$\sf \dashrightarrow {3a}^{2}{b}^{2} - 2ab + 10 - {2a}^{2}{b}^{2} + 2ab$

$\sf \dashrightarrow {3a}^{2}{b}^{2} - {2a}^{2}{b}^{2} - 2ab + 2ab + 10$

$\sf \dashrightarrow {1a}^{2}{b}^{2} - 0 + 10$

$\sf \dashrightarrow {a}^{2}{b}^{2} + 10$

7th Answer

$\sf \dashrightarrow 2 - {6m}^{2} + m + ({m}^{3} + {6m}^{2})$

$\sf \dashrightarrow 2 - {6m}^{2} + m + {m}^{3} + {6m}^{2}$

$\sf \dashrightarrow - {6m}^{2} + {6m}^{2} + {m}^{3} + 2 + m$

$\sf \dashrightarrow 0 + {m}^{3} + 2 + m$

$\sf \dashrightarrow {m}^{3} + 2 + m$