4p(q2-2r) solve it
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Solve the equation: 4x2−4px+(p2−q2)=0 · Answer · For the given quadratic equation, a=4 ,b=−4p and c=p2−q2 Thus, x=2a−b±b2−4a c ...
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For the given quadratic equation, a = 4,b = - 4p and c = p^2 - q^2 Thus, x = -b±√(b^2 - 4ac)2a = -(-4p)±√(( - 4p)^2 - 4 × 4 × (p^2 - q^2))2 .
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