4p2-20pq+25q2 give answerquestions
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2
Answer:
4p²-20pq+25q²
=(2p)²-2.2p.5q+(5q)²
=(2p-5q)²
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0
The factors of 4p² - 20pq + 25q² are (2p-5q) (2p-5q)
Given:
4p² - 20pq + 25q²
To find:
Factoring the equation
Solution:
Given 4p² - 20pq + 25q²
As we know
2² = 4 ⇒ 4p² = (2p)²
5² = 25 ⇒ 25q² = (5q)²
20 = (2×2×5) ⇒ 20pq = 2(2p)(5q)
4p² - 20pq + 25q²
⇒ (2p)²- 2(2p)(5q) + (5q)²
As we know from algebraic identities
(a-b)² = a² +b² -2ab
Take a = 2p and b = 5q and apply the formula
⇒ (2p - 5q)²
= (2p-5q) (2p-5q)
Therefore,
The factors of 4p² - 20pq + 25q² are (2p-5q) (2p-5q)
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