Question

4p²+ 5pq– 6pg²
factorise the following expression completly​

Answer 1

Answer:

the answer is in the attachment

Answer 2

Let us first find the HCF of all the terms of the given polynomial 4p2+5pq−6pq2 by factoring the terms as follows:

4p2=2×2×p×p5pq=5×p×q6pq2=2×3×p×q×q

Therefore, HCF=p

Now, we factor out the HCF from each term of the polynomial 4p2+5pq−6pq2 as shown below:

4p2+5pq−6pq2=p(4p+5q−6q2)

Hence, 4p2+5pq−6pq2=p(4p+5q−6q2).

hope it help uh freind