Question

4p²–9q² help me plz ​

Answer 1

$4 {p}^{2} - 9 {q}^{2} = (2p {)}^{2} - {(3q)}^{2} \\ x {}^{2} - {y}^{2} = (x + y)(x - y) \\ {(2p)}^{2} - ( {3q)}^{2} = (2p + 3q)(2p - 3q)$

Answer 2

$\bf4p²–9q² \\ \\ \bf 4 \implies {2}^{2} \\ \bf9 \implies {3}^{2} \\ \\ \bf \: substituting \: \: these \: \: in \: \: the \: \: given \: \: eqn. \\ \\ \bf{2}^{2} {p}^{2} - {3}^{2} {q}^{2} \\ \\ \bf \: taking \: \: square \: \: as \: \: common \: : \\ \\ \bf \: {(2p)}^{2} - {(3q)}^{2} \\ \\ \bf \: identity : {a}^{2} - {b}^{2} = (a + b)(a - b) \\ \\ \bf \: here : a = 2p \: \: \: \: \: b = 3q \\ \\ \bf \: {(2p)}^{2} - {(3q)}^{2} = \boxed{ \bf{(2p + 3q)(2p - 3q)}}$

$\\ \\ \\ \\ \color{aqua} \tt{Hope } \: \: \color{red}{ this} \: \: \color{lime} {helps }\: \: \color{hotpink}{you }$