Question

4p3 - 2p2 – 3 by (2p2 - 1)​

Answer 1

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((6p-(2•(p2)))-2p)-22p3)-p

STEP

2

:

Equation at the end of step

2

:

(((6p - 2p2) - 2p) - 22p3) - p

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

-4p3 - 2p2 + 3p = -p • (4p2 + 2p - 3)

Trying to factor by splitting the middle term

4.2 Factoring 4p2 + 2p - 3

The first term is, 4p2 its coefficient is 4 .

The middle term is, +2p its coefficient is 2 .

The last term, "the constant", is -3

Step-1 : Multiply the coefficient of the first term by the constant 4 • -3 = -12

Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is 2 .

-12 + 1 = -11

-6 + 2 = -4

-4 + 3 = -1

-3 + 4 = 1

-2 + 6 = 4

-1 + 12 = 11

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

-p • (4p2 + 2p - 3) friend I don't know the answer of your question but I know only this solution as same as this