(4power0+5power-1)×5power2×1/3
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$$\begin{lgathered}({4}^{0} + {5}^{ - 1} ) \times {5}^{2} \times \frac{1}{3} \\ =( 1 + \frac{1}{5} ) \times 25 \times \frac{1}{3} \\ = ( \frac{5 + 1}{5} ) \times 25 \times \frac{1}{3} \\ = (\frac{6}{5} \times 25 \times \frac{1}{3}) \\ = (2 \times 5) \\ = 10\end{lgathered}$$
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