Question

(4pq + 3q)2 – (4pq – 3q)2 =
48pq?
which identity is used in this sum ?
Give me full explanation.​

Answer 1

Answer:

(a+b)*2 - (a-b)*2=a+b a-b

Answer 2

Step-by-step explanation:

here we use (a+b)^2=a^2+b^2+2ab

and (a-b)^2=a^2+b^2-2ab

therefore (4pq+3q)2-(4pq-3q)^2=(4pq)^2+(3q)^2+2(4pq)(3q)-[(4q)^2+(3q)^2-2(4pq)(3q)]

=(4pq)^2+(3q)^2+24pq2-(4pq)^2-(3q)^2+24pq2

=48pq2