Math, asked by jitenathokpam88, 5 months ago

(4pq-5q²-3p²)-(5pq+3q²-pq)​

Answers

Answered by shritam42
0

Step-by-step explanation:

4pq(5pq+3q^2-pq)-

5q^2(5pq+3q^2-pq)-

3q^2(5pq+3q^2-pq)

=20p^2q^2+12pq^3-4p^2q^2-25pq^3+15q^4-5pq^3-15p^3q+9p^2q^2-3p^3q

=20p^2q^2+4p^2q^2+9p^2q^2+12pq^3-25pq^3-5pq^3-15p^3q+3p^3q+15q^4

=33p^2q^2+(-8pq^3)-33p^3q

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