Question

4q^2-p^2+2pr-r^2 Factorise the following ​

Answer 1

Answer:

4q²–p²+2pr–r²

= 4q²–(p–r)²

=(2q+p–r)(2q–p+r)

HOPE IT HELPS YOU.

Answer 2

Answer:

(2q+p-r)(2q-p+r)

Step-by-step explanation:

4q²-p²+2pr-r²

=(2q)²-p²-r²+2pr

=(2q)²-1(p²+r²-2pr)  

=(2q)²-(p-r)²  ∵[(a-b)²=a²+b²-2ab]

=(2q+p-r)(2q-p+r)  ∵a²-b²=(a+b)(a-b)