(4r+1) 4r+9) factorise using suitable identities
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Answer:
(4r+1)(4r+9)
(x+a)(x+b). = X²+(a+b)x+ab
=(4r)²+(1+9)4r+(1×9)
=16r²+40r+9
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(4r+1) (4r+9)
16r² + 36r + 4r +9
16r²+ 40r +9
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