Question

(4r+1) 4r+9) factorise using suitable identities​

Answer 1

Answer:

(4r+1)(4r+9)

(x+a)(x+b). = X²+(a+b)x+ab

=(4r)²+(1+9)4r+(1×9)

=16r²+40r+9

Step-by-step explanation:

I think it helps you

Answer 2

(4r+1) (4r+9)

16r² + 36r + 4r +9

16r²+ 40r +9