Question

4root12 - 7root6 by 5root6 - 2root12

Answer 1

Answer:

lgtaa nhi h sahi hog but kya pta sahi ho....give one thnxxx

Answer 2

$\\=4\sqrt{12}-7\sqrt{6}/5\sqrt{6}-2\sqrt{12}\\=4\sqrt{3*4} -7\sqrt{6}/5\sqrt{6}-2\sqrt{3*4}\\=8\sqrt{3}-7\sqrt{6}/5\sqrt{6}-4\sqrt{6}\\= 8\sqrt{3}-7\sqrt{6}/5\sqrt{6}-4\sqrt{6} * 5\sqrt{6}+4\sqrt{6}/ 5\sqrt{6}+4\sqrt{6} \\\\numerator \\=(8\sqrt{3}*5\sqrt{6} )+(8\sqrt{3}*4\sqrt{3} )+(+7\sqrt{6}*5\sqrt{6} )+(-7\sqrt{6}*4\sqrt{3} )\\=40\sqrt{18}+(32*3)-35\sqrt{36}-28\sqrt{18}\\\\ \\=12\sqrt{18}+96-35\sqrt{36}\\=12\sqrt{18}+96-(35*6)\\= 12\sqrt{18}+96-210\\=12\sqrt{18}-114 \\denominator$$(5\sqrt{6}-4\sqrt{3} )(5\sqrt{6}-4\sqrt{3} )\\(a-b)(a+b)=a^{2} -b^{2} \\(5\sqrt{6} )^{2} - (4\sqrt{3} )^{2} \\150-48\\102\\\\answer\\12\sqrt{18}-114/102$