Question

4root3 +or_ root12÷2

Answer 1

your answer will be 5√3

Answer 2

Hello,


The expression will be
$4 \sqrt{3} + - \sqrt{12} \div 2 \\ = 4 \sqrt{3} + - 2 \sqrt{3} \div 2 \\ = 2(2 \sqrt{ 3 } + - \sqrt{3} ) \div 2 \\ = 2 \sqrt{3} + \sqrt{3} = 3 \sqrt{3} \\ or \: 2 \sqrt{3} - \sqrt{3} = \sqrt{3}$
So,

We took 2 common in order to cut the 2 which is divide.
After this we were left with only 1 term that is
$2 \sqrt{3} + - \sqrt{3}$


The will be 2roo3 plus or minus root 3

So ,
The number will become 3root3 or root.

Please refer the above mathematical expression for the used process....

Hope this will be helping you ✌️