Math, asked by jhj, 1 year ago

4root3x2+5x-2root3
3x2+2root5x-5  factorisation method

Answers

Answered by Anonymous
1
Q1. 4√3x²+5x-2√3 = (4√3x²+8x)-(3x+2√3) = 4x(√3x+2) - √3(√3x+2) = (√3x+2)(4x-√3) Q2. 3x²+2√5x-5 = (3x²+5√5x) - (3√5x+5) = (3/√5)x(x√5+5/3) - 3(√5x+5/3) = 3(√5x+5/3)(x/√5-1)
jhj: 3x2+2root 5x -5=0
jhj: plz
Anonymous: The answer's here
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