Math, asked by Shreeshyam, 1 year ago

4root3xsquare +5x-2root3

Answers

Answered by fizafarheen
2
4root3x^2+5x-2root3x
=4root3x^2-8x+5x-2root3x
4x(root3x-2)+root3(root3x-2)
(4x+root3)(root3d-2)
x=-root3"4 or x=2/rokt3
Answered by nilesh102
0

hi mate,

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x -2√3=0

⇒4x(√3 x+2) -√3(√3x +2) =0

⇒(√3x +2)(4x -√3) =0

⇒(√3x +2) =0 or (4x-√3) =0

⇒x = -2/√3 or √3/4

i hope it helps you.

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