Question

4route 3x^2+5x-2route3 how to find

Answer 1

Solution:

4√3x²+5x-2√3

Splitting the middle term, we get

= 4√3x²+8x-3x-2√3

= 4x(√3x+2)-√3(√3x+2)

= (√3x+2)(4x-√3)

Therefore,

4√3x²+5x-2√3 = (√3x+2)(4x-√3)

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Answer 2

Hey there!!

Solution:-

$4\sqrt{3}x{}^{2}+5x-2\sqrt{3}$

$4\sqrt{3}x{}^{2}+8x-3x-2\sqrt{3}$

$4x(\sqrt{3}+2) -\sqrt{3}(\sqrt{3}+2)$

$(\sqrt{3}+2) (4x\sqrt-{3})$

$<marquee>Hope it's help uh$