4s^2-4s+1 find the zeroes of the quadratic polynomial
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Required Answer:-
Given:
- 4s² - 4s + 1 = 0
To find:
- The roots of the given equation.
Solution:
We have,
➡ 4s² - 4s + 1 = 0
➡ 4s² - 2s - 2s + 1 = 0
➡ 2s(2s - 1) - 1(2s - 1) = 0
➡ (2s - 1)(2s - 1) = 0
By zero product rule,
➡ Either (2s - 1) = 0 or (2s - 1) = 0 i.e, roots are equal.
Therefore,
s = ½, ½
Hence, the roots of the given equation are ½ and ½ (Equal Roots)
Answer:
- The roots of the given equation are ½ and ½ (Equal Roots)
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