Math, asked by aman8568, 4 months ago

4s^2-4s+1 find the zeroes of the quadratic polynomial​

Answers

Answered by anindyaadhikari13
9

Required Answer:-

Given:

  • 4s² - 4s + 1 = 0

To find:

  • The roots of the given equation.

Solution:

We have,

➡ 4s² - 4s + 1 = 0

➡ 4s² - 2s - 2s + 1 = 0

➡ 2s(2s - 1) - 1(2s - 1) = 0

➡ (2s - 1)(2s - 1) = 0

By zero product rule,

➡ Either (2s - 1) = 0 or (2s - 1) = 0 i.e, roots are equal.

Therefore,

s = ½, ½

Hence, the roots of the given equation are ½ and ½ (Equal Roots)

Answer:

  • The roots of the given equation are ½ and ½ (Equal Roots)
Answered by Anisha5119
6

Answer:

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