Question

4s^2-4s+1 find the zeros​

Answer 1

$\huge\mathcal{Solution}$

4s²-4s+1 = 0

4s²-2s-2s+1 = 0

2s(2s-1)-1(2s-1) = 0

(2s-1)(2s-1) = 0

2s-1 = 0

s = 1/2

Hope it helps you!!✌️

Answer 2

Answer:

4s²-4s+1 = 4s²-2s-2s+1

2s(2s-1)-1(2s-1)

(2s-1)(2s-1)

's = 1/2,1/2