Question

4s square-4s+1 by -b+or-rootbsquare -4ac alldivided by 2a

Answer 1

Given that,

4s² - 4s + 1 by using quadratic formula.

Let,

• a = 4
• b = - 4
• c = 1

$⟹ \frac{ - b ± \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ ⟹ \frac{ - ( - 4) ± \sqrt{ {( - 4)}^{2} - 4(4)(1) } }{2(4)} \\ \\ ⟹ \frac{4 ± \sqrt{16 - 16} }{8} \\ \\ ⟹ \frac{4}{8} \\ \\ ⟹ \frac{1}{2}$

Hence, it is solved...

Step-by-step explanation:

þLÈÄ§È MÄRK MÈ Ä§ ßRÄÌñLÌȧ†✌✌✌