Question

4s square - 4s +1 find zero

Answer 1

4s²-4s+1=4s²-2s-2s+1
=2s(2s-1)-1(2s-1)
=(2s-1)(2s-1)
Therefore,zeroes are 1/2 & 1/2

Answer 2

$\boxed{Hi \: friend}$

$\color{green}solution :$

$\star \: \underline{factorisation} \\ \\ 4s {}^{2} - 4s + 1 \\ \\ \implies4s {}^{2} - 2s - 2s + 1 \\ \\ \implies2s(2s - 1) - 1(2s - 1) \\ \\ \implies \: (2s - 1)(2s - 1) \\ \\ \: \implies(2s - 1) {}^{2} \\ \\ \underline{now} \\ \\ (2s - 1) {}^{2} = 0 \\ \\ \implies \: 2s - 1 = 0 \\ \\ \implies \: s = \frac{1}{2}$

therefore the zeroes are s = 1/2 and s = 1/2.

$\boxed{hope\: it\: helps}$