Question

4s³+15s²+16s+6=0
find value of s​

Answer 1

Answer:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((4 • (s3)) + (3•5s2)) + 16s) + 6 = 0

STEP

2

:

Equation at the end of step

2

:

((22s3 + (3•5s2)) + 16s) + 6 = 0

STEP

3

:

Checking for a perfect cube

3.1 4s3+15s2+16s+6 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 4s3+15s2+16s+6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 15s2+6

Group 2: 4s3+16s

Pull out from each group separately :

Group 1: (5s2+2) • (3)

Group 2: (s2+4) • (4s)