Question

4sin∅cos∅=1-2sin∅+2cos∅

∅=?​

Answer 1

let us assume Ø as θ

now,

4sinθ.cosθ=1-2sinθ+2cosθ

=>4sinθcosθ+2sinθ-2cosθ-1=0

=>2sinθ(2cosθ+1)-2cosθ -1=0

=>(2sinθ-1)(2cosθ+1)=0

=>sinθ=1/2. and cosθ=-1/2

if. sinθ=1/2 then θ=π/6

if. cosθ=-1/2 then θ=π-π/3. i.e.,θ=2π/3