Math, asked by munawwarali68981, 9 months ago

4sin theta( 1-2sin square theta under root 1-sin square theta

Answers

Answered by codiepienagoya
0

Simplify:

Step-by-step explanation:

\ Given \ value:\\\\4\sin \theta(1-2\sin^2\theta\sqrt{1}-sin^2\theta \\\\\ Solution:\\\\4\sin \theta(1-2\sin^2\theta\sqrt{1}-sin^2\theta \\\\\therefore \sqrt{1} = 1 \\\\\rightarrow 4\sin \theta(1-2\sin^2\theta\times 1 -sin^2\theta) \\\\\rightarrow 4\sin \theta(1-2\sin^2\theta -sin^2\theta) \\\\\rightarrow 4\sin \theta(1-\sin^2\theta(2 +1) )\\\\\rightarrow 4\sin \theta(1-3\sin^2\theta )\\\\

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