Question

4sin²o-2(√3+1) sino +3=0​

Answer 1

Answer:

taht statement it correct

Answer 2

Question -

4 sin^2θ - 2(√3 + 1)  sin θ+ 3 =0

Answer:

Step-by-step explanation:

4 sin^2θ - 2(√3 + 1)  sin θ+ 3 =0

$4Sin^{2}\theta -2(\sqrt{3}+1)Sin\theta +\sqrt{3} = 04Sin2θ−2(3+1)Sinθ+3=04Sin^{2}\theta -2\sqrt{3}Sin\theta - 2Sin\theta + \sqrt{3} = 04Sin2θ−23Sinθ−2Sinθ+3=02Sin\theta(2Sin\theta -\sqrt{3}) -1(2Sin\theta - \sqrt{3} = 02Sinθ(2Sinθ−3)−1(2Sinθ−3=0(2Sin\theta - \sqrt{3}) (2Sin\theta - 1) = 0(2Sinθ−3)(2Sinθ−1)=0If, 2Sin\theta - \sqrt{3} = 02Sinθ−3=02Sin\theta = \sqrt{3}2Sinθ=3Sin\theta = \dfrac{\sqrt{3} }{2}Sinθ=23Sin\theta = Sin\dfrac{\pi }{3}Sinθ=Sin$