Question

4sinA×sin(60-A)×sin(60+A)-sin3A=0​

Answer 1

here is the answer... please mark it as a brilliant answer

Answer 2

Answer:

4sinA. sin(60-A).sin(60+a)-sin3A

Step-by-step explanation:

=4sinA(sin'2 60-sin'2 A)-(3sinA-4sin'3A)

=4sinA(3/4-sin'2A)-3sinA+4sin'3A

=4sinA. 3/4-4sin'3A-3sinA+4sin'3A

=3sinA-3sinA=0 (proved)