Question

4sinxcosx=√3 then x=?​

Answer 1

Given,

4sinxcosx = √3

It can also, be written as,

2(2sinxcosx)

Now we know,

2sinxcosx = sin2x

Then,

2(2sinxcosx) = 2sin2x = √3

2sin2x = √3

sin2x = √3/2

we know,

Sin60° = √3/2

2x = 60°

x= 30°

Cheers!

Answer 2

The value of $x$ is $=30^{o}$.

Step-by-step explanation:

Given:

$4sin(x)cos(x)=\sqrt{3}$

To find:

To find the value of $x$.

Solution:

Step 1:

$4sin(x)cos(x)=\sqrt{3}$

Multiply each term by $\frac{1}{2}$.

$4sin(x)cos(x)\times\frac{1}{2} =\sqrt{3}\times \frac{1}{2}$

we get, $2sin(x)cos(x)=\sqrt{3} \times\frac{1}{2}$

We know that $2sin(x)cos(x)=sin2x$

So, it can be written as $sin(2x)=\frac{\sqrt{3} }{2}$.

Step 2:

We know that sin $sin(60^{o})=\frac{\sqrt{3} }{2}$

$2x=60^{o}$

$x=30^{o}$

Hence, the value of $x$ is $30^{o}$.

#SPJ3