Math, asked by ketanj2005, 1 year ago

4st(s-t)-6s*(t-t*)-3t*(2s*-s)+2st(s-t)

Answers

Answered by okaps
41
We have  :   4st ( s - t ) - 6s2 ( t  - t2 ) - 3t2 ( 2s2 - s ) + 2 st2 (  s - t )  , So

⇒4s2t −4st2 − 6s2t   +6s2t2 − 6s2t2 +3st2 + 2s2t2 −2s t3
⇒− 2s2t −st2  + 2s2t2 −2s t3
⇒s t (− 2s  −t   + 2st−2  t2)
⇒s t ( 2st− 2s  −2  t2−t )                 ( Ans )



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