Question

4st(s-t)-6s²(t-t²)-3t²(2s²-s)+2st(s-t)​

Answer 1

We have : 4st ( s - t ) - 6s2 ( t - t2 ) - 3t2 ( 2s2 - s ) + 2 st2 ( s - t ) , So

⇒4s2t −4st2 − 6s2t +6s2t2 − 6s2t2 +3st2 + 2s2t2 −2s t3⇒− 2s2t −st2 + 2s2t2 −2s t3⇒s t (− 2s −t + 2st−2 t2)⇒s t ( 2st− 2s −2 t2−t ) ( Ans )