Question

(4t^2+6p^2-12p^2t^2q) by -1/2pqt

Answer 1

Answer:

$\frac{4 {t}^{2} + 6 {p}^{2} - 12 {p}^{2} {t}^{2} q }{ - \frac{1}{2}pqt }$

$\frac{4 {t}^{2} }{ - \frac{1}{2} pqt} + \frac{6 {p}^{2} }{ - \frac{1}{2}pqt } - \frac{12 {p}^{2} {t}^{2} q}{ - \frac{1}{2}pqt }$

$- 8 {p}^{ - 1} {q}^{ - 1} t - 12p {q}^{ - 1} {t}^{ - 1} + 24pt$

Answer 2

$</p><p>Answer:</p><p></p><p>\frac{4 {t}^{2} + 6 {p}^{2} - 12 {p}^{2} {t}^{2} q }{ - \frac{1}{2}pqt } </p><p>− </p><p>2</p><p>1</p><p> </p><p> pqt</p><p>4t </p><p>2</p><p> +6p </p><p>2</p><p> −12p </p><p>2</p><p> t </p><p>2</p><p> q</p><p> </p><p> </p><p></p><p>\frac{4 {t}^{2} }{ - \frac{1}{2} pqt} + \frac{6 {p}^{2} }{ - \frac{1}{2}pqt } - \frac{12 {p}^{2} {t}^{2} q}{ - \frac{1}{2}pqt } </p><p>− </p><p>2</p><p>1</p><p> </p><p> pqt</p><p>4t </p><p>2</p><p> </p><p> </p><p> + </p><p>− </p><p>2</p><p>1</p><p> </p><p> pqt</p><p>6p </p><p>2</p><p> </p><p> </p><p> − </p><p>− </p><p>2</p><p>1</p><p> </p><p> pqt</p><p>12p </p><p>2</p><p> t </p><p>2</p><p> q</p><p> </p><p> </p><p></p><p>- 8 {p}^{ - 1} {q}^{ - 1} t - 12p {q}^{ - 1} {t}^{ - 1} + 24pt−8p </p><p>−1</p><p> q </p><p>−1</p><p> t−12pq </p><p>−1</p><p> t </p><p>−1</p><p> +24pt</p><p> </p><p>$

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