Question

4t/(t^2-25)=1/(5-t) please solve this.​

Answer 1

Answer:

t = -1 , 5

Step-by-step explanation:

$\frac{4t}{ ({t}^{2} - 25) } = \frac{1}{(5 - t)} \\ cross \: multiplying \\ 4t(5 - t) = {t}^{2} - 25 \\ 20t - 4 {t}^{2} = {t}^{2} - 25 \\ 20t - 4 {t}^{2} - {t}^{2} + 25 = 0 \\ 20t - 5 {t}^{2} + 25 = 0 \\ 5 {t}^{2} - 20t - 25 = 0 \\ 5( {t}^{2} - 4t - 5) = 0 \\ {t}^{2} - 4t - 5 = 0 \\ {t}^{2} - 5t + t - 5 = 0 \\ t(t - 5) + (t - 5) = 0 \\ (t + 1)(t - 5) = 0$

so, t = -1, 5