Question

4tan squareA + 3 is equal to:​

Answer 1

$4 { \tan}^{2} a \: + 3=0 \\ = 4 { \tan }^{2}a = - 3 \\ = { \tan}^{2}a = \frac{ - 3}{4} \\ = \tan(a) = \frac{ \sqrt{ - 3} }{ \sqrt{4} } \\ = \tan(a) = \frac{ \sqrt{ - 3} }{2}$

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Answer 2

Answer:

3sec^2A + tan^2A

Step-by-step explanation:

Please find the attached image.