Question

4th ques pls solve it urgent
i will give you 50 thanks
no irrelevant ans pls​

Answer 1

${\Large{\bf{Question}}}$

${\small{\blacksquare \: \: {\sf{20x + 25y = 200}}}}$

${\Large{\bf{Solution}}}$

${\small{\hookrightarrow{\tt{5(4x+5y) = 200}}}}$

${\small{\hookrightarrow{\tt{4x+5y = \dfrac{200}{5}}}}}$

${\small{\hookrightarrow{\tt{4x+5y = 40}}}}$

Let, x = 0

Then, 4(0) + 5y = 40

→ 0 + 5y = 40

→ y = 40/5

→ y = 8

Let, y = 0

Then, 4x + 5(0) = 40

→ 4x = 40

→ x = 40/4

→ x = 10

$\begin{array}{|c|c|c|}\hline x & 0 & 10 \\ \hline y & 8 & 0 \\ \hline \end{array}$

You can draw a graph by using the above information

Answer 2

QUESTION:

• Draw the graph of the linear equation 20x + 25y = 200.

TO DRAW:

• Graph for the linear equation 20x + 25y = 200.

EXPLANATION:

20x + 25y = 200 is the given line equation.

Put x = 0

20(0) + 25y = 200

25y = 200y = 8

Now Put y = 0

20x + 25(0) = 200

20x = 200x = 10

Now we got two points - (0, 8) and (10, 0)

Plot the two points in the graph and joint them we get a line with equation 20x + 25y = 200.