Question

4th question find the height of the solid formed when we make a stack​

Answer 1

Answer:

240 height of cylinders

Answer 2

Answer:

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Principal=2004.15\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Difference= 33 \: rupees \\ \\ \tt: \implies Rate\%(r) = 20\% \\ \\ \tt: \implies Time(t) = 18 \: months \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Principal(p)= ?$

• According to given question :

$\tt \circ \: Time = \frac{18}{12} \: years \\ \\ \bold{For \: compounded \: yearly} \\ \tt: \implies A= p(1 + \frac{r}{100})^{t} \\ \\ \tt: \implies A =p( 1 + \frac{20}{100} )^{ \frac{18}{12} } \\ \\ \tt: \implies A= p(1 + 0.2)^{ \frac{18}{12} } \\ \\ \tt: \implies A =p \times (1.2)^{ \frac{18}{12} } \\ \\ \tt: \implies A=1.314534138p - - - - - (1)$

$\bold{For \: Compounded \:half-yearly } \\ \tt: \implies A= p(1 + \frac{ \frac{r}{2} }{100} )^{2t} \\ \\ \tt: \implies A=p \times (1 + \frac{20}{2 \times 100} )^{2 \times \frac{18}{12}} \\ \\ \tt: \implies A =p \times (1 + 0.1)^{3} \\ \\ \tt: \implies A=p \times {(1.1)}^{3} \\ \\ \tt: \implies A =p \times 1.331 \\ \\ \tt: \implies A=1.331p-----(2)$

$\bold{For \: Difference : } \\ \tt: \implies 1.331p - 1.314534138p = 33 \\ \\ \tt: \implies 0.016465862p = 33 \\ \\ \tt: \implies p = \frac{33}{0.016465862} \\ \\ \green{\tt: \implies p = 2004.15 \: rupees}$