Question

4th question
if You will solve it i willmake it as brainlist question​

Answer 1

Answer:

Given:

2 vectors have been supplied such that one is x N and another is 5 N. The resultant ia also 5 N and is perpendicular to 5N vector.

To find:

Angle between x N and 5 N

Concept:

First we will try to draw the diagram illustrating the vectors Then using Trigonometry, we will try to find out the angle.

Calculation:

First let's calculate the value of x N. It can be easily done using Pythagoras theorem.

$x = \sqrt{ {5}^{2} + {5}^{2} } = 5 \sqrt{2} \: N$

Now applying trigonometry to find angle θ.

$\cos( \theta) = \dfrac{base}{hypotenuse}$

$= > \cos( \theta) = \dfrac{5}{5 \sqrt{2} }$

$= > \cos( \theta) = \dfrac{1}{ \sqrt{2} }$

$= > \theta \: = 45 \degree$

So total angle between x N and 5 N is :

$\angle ABC = \theta + 90 \degree$

$= > \angle ABC = (45+ 90) \degree$

$= > \angle ABC = 135 \degree$

So final answer :

$\boxed{ \red{ \huge{ \bold{ \angle ABC = 135 \degree}}}}$

Answer 2

The required figure is in the attachment.

The figure is that if an isosceles triangle.

Hence X = 5√2 .

We know that :

$\tt{ \red{ \cos( \alpha ) = \frac{base}{hypotenuse} = \frac{5}{5 \sqrt{2} } = \frac{1}{ \sqrt{2} } }}$

Therefore alpha = 45°

Required Angle = 90° + 45° = 135°