4th term 2 ,7th term 3 find common difference in this arithmetic sequence
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Answer:
Solving the above two equations we get,
a = 6
d = 4
Sum of n terms (Sn) is given by
Sn = (n/2)*(2*a + (n-1)*d)
=(n/2)*(12 + (n-1)*4)
= n*(6 + 2*n -2)
= 2*n*( n + 2 )
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