4th term in the expansion of (root x+1/x)^12
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this is just a example
How do you find the 4th term in the expansion of the binomial (x+y)10?
Use the binomial theorem: 210x4y6
Explanation:
Using the Binomial Theorem, you can quickly calculate the 4th term (or any kth term).
The Binomial Theorem states that any binomial of the form (x+a)v can be expanded to
∞∑k=0(vk)xkav−k
In trying to find the 4th term, we let k=4 and in the binomial (x+y)10, the term a=y and v=10. This gives us
(vk)xkav−k=(104)x4y10−4=10!(10−4)!4!x4y6
=10!6!4!x4y6=210x4y6
I hope this will help you
if not then comment me
How do you find the 4th term in the expansion of the binomial (x+y)10?
Use the binomial theorem: 210x4y6
Explanation:
Using the Binomial Theorem, you can quickly calculate the 4th term (or any kth term).
The Binomial Theorem states that any binomial of the form (x+a)v can be expanded to
∞∑k=0(vk)xkav−k
In trying to find the 4th term, we let k=4 and in the binomial (x+y)10, the term a=y and v=10. This gives us
(vk)xkav−k=(104)x4y10−4=10!(10−4)!4!x4y6
=10!6!4!x4y6=210x4y6
I hope this will help you
if not then comment me
debashish12:
I do know it already bro. The formulae you have just shared. The only problem i am facing is solving this question. Please do help if u can Please
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