4th term of an ap is zero then prove that 25th term is 3 times the 11 tyh term
Answers
Answered by
1
4th term of an a.p = a^4 = 0
a+3d = 0
a= -3d
25th of an a.p = a^25 = 0
a+24d =0
-3d + 24d = 0
= 21d
3 times 11th of an a.p = 3a^11
= 3(a+10d)
= 3(-3d+10d)
= 3×7d
= 21d
hence proved
plzz mark as brainliest answer !!!
a+3d = 0
a= -3d
25th of an a.p = a^25 = 0
a+24d =0
-3d + 24d = 0
= 21d
3 times 11th of an a.p = 3a^11
= 3(a+10d)
= 3(-3d+10d)
= 3×7d
= 21d
hence proved
plzz mark as brainliest answer !!!
Answered by
1
Given :- a4 = 0
To prove :- a25 = 3 ( a 11 )
an = a + ( n - 1 )d
a4 = a + 3d
0 = a + 3d
a = - 3d
___________
• a 25 = a + 24d
- 3d + 24d = 21d
____________
• a11 = a + 10d
- 3d + 10d = 7d
____________
Since , a25 = 3 ( a11 )
21d = 3 ( 7d )
Hence proved !
To prove :- a25 = 3 ( a 11 )
an = a + ( n - 1 )d
a4 = a + 3d
0 = a + 3d
a = - 3d
___________
• a 25 = a + 24d
- 3d + 24d = 21d
____________
• a11 = a + 10d
- 3d + 10d = 7d
____________
Since , a25 = 3 ( a11 )
21d = 3 ( 7d )
Hence proved !
Similar questions